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111997-40-1

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111997-40-1 Usage

Check Digit Verification of cas no

The CAS Registry Mumber 111997-40-1 includes 9 digits separated into 3 groups by hyphens. The first part of the number,starting from the left, has 6 digits, 1,1,1,9,9 and 7 respectively; the second part has 2 digits, 4 and 0 respectively.
Calculate Digit Verification of CAS Registry Number 111997-40:
(8*1)+(7*1)+(6*1)+(5*9)+(4*9)+(3*7)+(2*4)+(1*0)=131
131 % 10 = 1
So 111997-40-1 is a valid CAS Registry Number.

111997-40-1Upstream product

111997-40-1Downstream Products

111997-40-1Relevant articles and documents

Tungsten and molybdenum alkylidyne complexes containing bulky thiolate ligands

Murdzek, John S.,Blum, Lauren,Schrock, Richard R.

, p. 436 - 441 (1988)

Complexes of the type Mo(C-t-Bu)(TMT)3 and Mo(C-t-Bu)(TIPT)3 (TMT = 2,4,6-trimethylbenzenethiolate; TIPT = 2,4,6-triisopropylbenzenethiolate) can be prepared by adding 3 equiv of LiSAr (SAr = TMT or TIPT) to Mo(C-t-Bu)Cl3(dme). The TMT derivative is believed to be dimeric on the basis of NMR spectra. Reactions between M(C-t-Bu)Cl3(dme) (M = Mo or W), ArSH, and NEt3 yield complexes of the type [Et3NH][M(C-t-Bu)(SAr)3Cl]. W(C-t-Bu)(SAr)3 complexes can be prepared by removing chloride ion from the [Et3NH][W(C-t-Bu)(SAr)3Cl] species with zinc chloride. M(C-t-Bu)(SAr)3 complexes do not react with 3-hexyne, 2-butyne, or phenylacetylene, and only minute traces of 3-heptyne metathesis products are observed after 3 days at 25°C. The reaction between W(C3Me3)Cl3 and LiTIPT yields W(C3Me3)(TIPT)3 (in situ), the reaction between W(C3Me3)Cl3, TIPTH, and NEt3 (or that between W(C3Me3)(TIPT)3 and Et3NHCl) gives [Et3NH][W(CMe)(TIPT)3Cl], and the reaction between the η3-cyclopropenyl complex W(C3-t-BuMe2)Cl3(py)2 and LiTMT yields a mixture of W(CMe)(TMT)3(py) and W(C-t-Bu)(TMT)3(py). Both Mo(CPr)(TIPT)3 and W(CMe)(TIPT)3 are stable and isolable. We conclude from these studies that M(CR)(SAr)3 complexes react too slowly with ordinary acetylenes to be active catalysts, either because coordination of sulfur (in a dimer) competes effectively with coordination of the acetylene or because the metal is simply not electrophilic enough, or both.

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