521916-35-8Relevant articles and documents
Complexes derived from the reactions of diphenylphosphinoacetic acid. Part 4. Mononuclear complexes of Rh(I), Ir(I) and Ir(III) and some related chemistry involving the diphenyl(2,6-dimethylphenyl)-phosphine ligand
Kuang, Shan-Ming,Edwards, Dennis A.,Fanwick, Phillip E.,Walton, Richard A.
, p. 275 - 280 (2003)
The iridium complex [IrCl(COD)]2 reacts with diphenylphosphinoacetic acid (1) in the presence of CO to afford the iridium(III) complex IrHCl(CO)(η2-Ph2PCH2CO2) (η1-Ph2PCH2CO2H) (3) which in the solid state exists as a hydrogen-bonded dimer. Complex 3 converts to IrH(CO)(η2-Ph2PCH2CO2) 2 (4) when treated with AgO3SCF3 in dichloromethane. The tertiary phosphine PPh2(Ph-2,6-Me2) (2) reacts with solutions of [RhCl(CO)2]2 and [IrCl(COD)]2 (in the presence of CO) in dichloromethane to give the square planar complexes MCl(CO)[PPh2(Ph-2,6-Me2)]2 (M=Rh (5) or Ir (6)) in high yield. While the iridium(I) complex 6 undergoes an oxidative-addition reaction with HgCl2 to yield the complex IrCl2(HgCl)(CO)[PPh2(Ph-2,6-Me2)] 2 (7), complex 5 is unreactive towards this reagent.